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XML Filter Fast Way?(and their child nodes) if an attribute is not contained/matched. I would like to output a new XML document, not modifying the original. Can anyone recommend XSLT for this or a programmatic way if it's faster? <item look="a;b"> <item look="a;b"> <subitem/> <subitem/> <item look="a"> <subitem/> </subitem/> </item> </item> <item> I would like to apply an expression to the above document, so any <item> element that does not have a "b" in the look attribute is removed. I would like the result XML document to be: <item look="a;b"> <item look="a;b"> <subitem/> <subitem/> </item> <item> Thanks. i guess you can use xpath queries ....
Show quote "xeroxero" <xeroxero@newsgroups.nospam > wrote in message news:i1htk2lqh5gga4dcpnm7virlnrb9lb88vc@4ax.com... > > > I have an XML document that I would like to remove/filter whole nodes > (and their child nodes) if an attribute is not contained/matched. I > would like to output a new XML document, not modifying the original. > Can anyone recommend XSLT for this or a programmatic way if it's > faster? > > > <item look="a;b"> > <item look="a;b"> > <subitem/> > <subitem/> > <item look="a"> > <subitem/> > </subitem/> > </item> > </item> > <item> > > I would like to apply an expression to the above document, so any > <item> element that does not have a "b" in the look attribute is > removed. I would like the result XML document to be: > > <item look="a;b"> > <item look="a;b"> > <subitem/> > <subitem/> > </item> > <item> > > > Thanks. > > > > > > > > > > > > > That is not going to work. The original XML document is generated
dynamically. I think I need to do XSLT or some kind of iterative/dynamic XPath technology. Can anyone provide a sample? Show quote On Mon, 6 Nov 2006 05:19:01 -0600, "Mubashir Khan" <m***@yahoo.com> wrote: >i guess you can use xpath queries .... >"xeroxero" <xeroxero@newsgroups.nospam > wrote in message >news:i1htk2lqh5gga4dcpnm7virlnrb9lb88vc@4ax.com... >> >> >> I have an XML document that I would like to remove/filter whole nodes >> (and their child nodes) if an attribute is not contained/matched. I >> would like to output a new XML document, not modifying the original. >> Can anyone recommend XSLT for this or a programmatic way if it's >> faster? >> >> >> <item look="a;b"> >> <item look="a;b"> >> <subitem/> >> <subitem/> >> <item look="a"> >> <subitem/> >> </subitem/> >> </item> >> </item> >> <item> >> >> I would like to apply an expression to the above document, so any >> <item> element that does not have a "b" in the look attribute is >> removed. I would like the result XML document to be: >> >> <item look="a;b"> >> <item look="a;b"> >> <subitem/> >> <subitem/> >> </item> >> <item> >> >> >> Thanks. >> >> >> >> >> >> >> >> >> >> >> >> >> >  |
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