Creating a nullable type using Activator

19 May 2006 4:44 PM

DerekG

Hi

I am trying to create an instance of a nullable type using System.Activator
for example

t is passed in from the caller and is the Type info for a nullable type or
can be a standard type i.e string, int etc.

object value = Activator.CreateInstance(t);

value always returns null

19 May 2006 4:58 PM

Mattias Sjögren

>value always returns null

That makes sense since you haven't specified a value for the instance.

Mattias

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Mattias Sjögren [C# MVP] mattias @ mvps.org
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19 May 2006 5:10 PM

Giuseppe Lippolis

Hello DerekG,
object o = typeof(Nullable<>).MakeGenericType(new Type[] { typeof(int)
});

Show quote

> Hi
>
> I am trying to create an instance of a nullable type using
> System.Activator for example
>
> t is passed in from the caller and is the Type info for a nullable
> type or can be a standard type i.e string, int etc.
>
> object value = Activator.CreateInstance(t);
>
> value always returns null
>

22 May 2006 1:09 PM

DerekG

Hi Giuseppe,

Thanks for the reply, this has helped me solve the problem. Thanks for your
help.

Show quote

"Giuseppe Lippolis" wrote:

> Hello DerekG,
> object o = typeof(Nullable<>).MakeGenericType(new Type[] { typeof(int)
> });
>
> > Hi
> >
> > I am trying to create an instance of a nullable type using
> > System.Activator for example
> >
> > t is passed in from the caller and is the Type info for a nullable
> > type or can be a standard type i.e string, int etc.
> >
> > object value = Activator.CreateInstance(t);
> >
> > value always returns null
> >
>
>
>